(x-2)/3+(y+5)/6-(z+3)/2=10

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Solution for (x-2)/3+(y+5)/6-(z+3)/2=10 equation: 


x in (-oo:+oo)

(x-2)/3+(y+5)/6-((z+3)/2) = 10 // - 10

(x-2)/3+(y+5)/6-((z+3)/2)-10 = 0

(x-2)/3+(y+5)/6+(-1*(z+3))/2-10 = 0

(2*6*(x-2))/(2*3*6)+(2*3*(y+5))/(2*3*6)+(-1*3*6*(z+3))/(2*3*6)+(-10*2*3*6)/(2*3*6) = 0

2*6*(x-2)+2*3*(y+5)-1*3*6*(z+3)-10*2*3*6 = 0

12*x+6*y-18*z-360-54+6 = 0

12*x+6*y-18*z-360-48 = 0

12*x+6*y-18*z-408 = 0

(12*x+6*y-18*z-408)/(2*3*6) = 0

(12*x+6*y-18*z-408)/(2*3*6) = 0 // * 2*3*6

12*x+6*y-18*z-408 = 0

12*x+6*y-18*z-408 = 0 // - 6*y-18*z-408

12*x = -(6*y-18*z-408) // : 12

x = (-(6*y-18*z-408))/12

x = (408-(6*y)-(-18*z))/12

x = (408-(6*y)-(-18*z))/12

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