(x-2)/8=(x-4)/3-1

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Solution for (x-2)/8=(x-4)/3-1 equation: 



(x-2)/8=(x-4)/3-1

We move all terms to the left:

(x-2)/8-((x-4)/3-1)=0

We calculate fractions


(3x-6)/()+(-((x-4)*8)/()=0



We calculate terms in parentheses: +(-((x-4)*8)/(), so:

-((x-4)*8)/(

We multiply all the terms by the denominator


-((x-4)*8)



We calculate terms in parentheses: -((x-4)*8), so:

(x-4)*8

We multiply parentheses

8x-32

Back to the equation:

-(8x-32)



We get rid of parentheses

-8x+32

Back to the equation:

+(-8x+32)



We get rid of parentheses

(3x-6)/()-8x+32=0

We multiply all the terms by the denominator


(3x-6)-8x*()+32*()=0

We add all the numbers together, and all the variables

(3x-6)-8x*()=0

We get rid of parentheses

3x-8x*()-6=0

We move all terms containing x to the left, all other terms to the right

3x-8x*()=6

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