(x-2)=(x2+4x-8)

Solution for (x-2)=(x2+4x-8) equation:

(x-2)=(x2+4x-8)

We move all terms to the left:

(x-2)-((x2+4x-8))=0

We add all the numbers together, and all the variables

-((+x^2+4x-8))+(x-2)=0

We get rid of parentheses

-((+x^2+4x-8))+x-2=0


We calculate terms in parentheses: -((+x^2+4x-8)), so:

(+x^2+4x-8)

We get rid of parentheses

x^2+4x-8

Back to the equation:

-(x^2+4x-8)


We add all the numbers together, and all the variables

x-(x^2+4x-8)-2=0

We get rid of parentheses

-x^2+x-4x+8-2=0

We add all the numbers together, and all the variables

-1x^2-3x+6=0

a = -1; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·(-1)·6
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*-1}=\frac{3-\sqrt{33}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*-1}=\frac{3+\sqrt{33}}{-2}
$