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(x-2)x=168
We move all terms to the left:
(x-2)x-(168)=0
We multiply parentheses
x^2-2x-168=0
a = 1; b = -2; c = -168;
Δ = b2-4ac
Δ = -22-4·1·(-168)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-26}{2*1}=\frac{-24}{2} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+26}{2*1}=\frac{28}{2} =14 $
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