(x-2/x+2)+(4/x+2)+4=0

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Solution for (x-2/x+2)+(4/x+2)+4=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(2/x)+4/x+2+2+4 = 0

x-2*x^-1+4/x+2+2+4 = 0

1*x^1+2*x^-1+8*x^0 = 0

(1*x^2+8*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+8*x^1+2*x^0) = 0

x^1

x^2+8*x+2 = 0

x^2+8*x+2 = 0

DELTA = 8^2-(1*2*4)

DELTA = 56

DELTA > 0

x = (56^(1/2)-8)/(1*2) or x = (-56^(1/2)-8)/(1*2)

x = (2*14^(1/2)-8)/2 or x = (-2*14^(1/2)-8)/2

x in { (-2*14^(1/2)-8)/2, (2*14^(1/2)-8)/2} 

x in { (-2*14^(1/2)-8)/2, (2*14^(1/2)-8)/2 }

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