(x-22)+(2x-19)=(1/2x+11)

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Solution for (x-22)+(2x-19)=(1/2x+11) equation: 



(x-22)+(2x-19)=(1/2x+11)

We move all terms to the left:

(x-22)+(2x-19)-((1/2x+11))=0



Domain of the equation: 2x+11))!=0

x∈R



We get rid of parentheses

x+2x-((1/2x+11))-22-19=0

We multiply all the terms by the denominator


x*2x+11))+2x*2x+11))-((1-22*2x+11))-19*2x+11))=0

We add all the numbers together, and all the variables

x*2x+11))+2x*2x+11))-((-22*2x+12))-19*2x+11))=0

Wy multiply elements

2x^2+11))+2x*2x+11))-((-22*2x+12))-19*2x+11))=0

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