(x-22)+(2x-215)+(1/2x+11)=180

Solution for (x-22)+(2x-215)+(1/2x+11)=180 equation:

(x-22)+(2x-215)+(1/2x+11)=180

We move all terms to the left:

(x-22)+(2x-215)+(1/2x+11)-(180)=0


Domain of the equation: 2x+11)!=0

x∈R


We get rid of parentheses

x+2x+1/2x-22-215+11-180=0

We multiply all the terms by the denominator


x*2x+2x*2x-22*2x-215*2x+11*2x-180*2x+1=0

Wy multiply elements

2x^2+4x^2-44x-430x+22x-360x+1=0

We add all the numbers together, and all the variables

6x^2-812x+1=0

a = 6; b = -812; c = +1;
Δ = b2-4ac
Δ = -8122-4·6·1
Δ = 659320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{659320}=\sqrt{4*164830}=\sqrt{4}*\sqrt{164830}=2\sqrt{164830}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-812)-2\sqrt{164830}}{2*6}=\frac{812-2\sqrt{164830}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-812)+2\sqrt{164830}}{2*6}=\frac{812+2\sqrt{164830}}{12}
$