(x-2i)(3+i)=20

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Solution for (x-2i)(3+i)=20 equation: 


Simplifying
(x + -2i)(3 + i) = 20

Reorder the terms:
(-2i + x)(3 + i) = 20

Multiply (-2i + x) * (3 + i)
(-2i * (3 + i) + x(3 + i)) = 20
((3 * -2i + i * -2i) + x(3 + i)) = 20
((-6i + -2i2) + x(3 + i)) = 20
(-6i + -2i2 + (3 * x + i * x)) = 20

Reorder the terms:
(-6i + -2i2 + (ix + 3x)) = 20
(-6i + -2i2 + (ix + 3x)) = 20

Reorder the terms:
(-6i + ix + -2i2 + 3x) = 20
(-6i + ix + -2i2 + 3x) = 20

Solving
-6i + ix + -2i2 + 3x = 20

Solving for variable 'i'.

Reorder the terms:
-20 + -6i + ix + -2i2 + 3x = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + -6i + ix + -2i2 + 3x = 0

The solution to this equation could not be determined.

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