(x-3)(-x+1)=1

Solution for (x-3)(-x+1)=1 equation:

(x-3)(-x+1)=1

We move all terms to the left:

(x-3)(-x+1)-(1)=0

We add all the numbers together, and all the variables

(x-3)(-1x+1)-1=0

We multiply parentheses ..

(-1x^2+x+3x-3)-1=0

We get rid of parentheses

-1x^2+x+3x-3-1=0

We add all the numbers together, and all the variables

-1x^2+4x-4=0

a = -1; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{-2}=+2$