(x-3)(4-x)=2-(x+5)(x-1)

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Solution for (x-3)(4-x)=2-(x+5)(x-1) equation: 



(x-3)(4-x)=2-(x+5)(x-1)

We move all terms to the left:

(x-3)(4-x)-(2-(x+5)(x-1))=0

We add all the numbers together, and all the variables

(x-3)(-1x+4)-(2-(x+5)(x-1))=0

We multiply parentheses ..

(-1x^2+4x+3x-12)-(2-(x+5)(x-1))=0



We calculate terms in parentheses: -(2-(x+5)(x-1)), so:

2-(x+5)(x-1)

determiningTheFunctionDomain
-(x+5)(x-1)+2

We multiply parentheses ..

-(+x^2-1x+5x-5)+2

We get rid of parentheses

-x^2+1x-5x+5+2

We add all the numbers together, and all the variables

-1x^2-4x+7

Back to the equation:

-(-1x^2-4x+7)



We get rid of parentheses

-1x^2+1x^2+4x+3x+4x-12-7=0

We add all the numbers together, and all the variables

11x-19=0

We move all terms containing x to the left, all other terms to the right

11x=19

x=19/11

x=1+8/11

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