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(x-3)(4x+20)=0
We multiply parentheses ..
(+4x^2+20x-12x-60)=0
We get rid of parentheses
4x^2+20x-12x-60=0
We add all the numbers together, and all the variables
4x^2+8x-60=0
a = 4; b = 8; c = -60;
Δ = b2-4ac
Δ = 82-4·4·(-60)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*4}=\frac{-40}{8} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*4}=\frac{24}{8} =3 $
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