(x-3)(x+1)(x-4)=0

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Solution for (x-3)(x+1)(x-4)=0 equation: 


Simplifying
(x + -3)(x + 1)(x + -4) = 0

Reorder the terms:
(-3 + x)(x + 1)(x + -4) = 0

Reorder the terms:
(-3 + x)(1 + x)(x + -4) = 0

Reorder the terms:
(-3 + x)(1 + x)(-4 + x) = 0

Multiply (-3 + x) * (1 + x)
(-3(1 + x) + x(1 + x))(-4 + x) = 0
((1 * -3 + x * -3) + x(1 + x))(-4 + x) = 0
((-3 + -3x) + x(1 + x))(-4 + x) = 0
(-3 + -3x + (1 * x + x * x))(-4 + x) = 0
(-3 + -3x + (1x + x2))(-4 + x) = 0

Combine like terms: -3x + 1x = -2x
(-3 + -2x + x2)(-4 + x) = 0

Multiply (-3 + -2x + x2) * (-4 + x)
(-3(-4 + x) + -2x * (-4 + x) + x2(-4 + x)) = 0
((-4 * -3 + x * -3) + -2x * (-4 + x) + x2(-4 + x)) = 0
((12 + -3x) + -2x * (-4 + x) + x2(-4 + x)) = 0
(12 + -3x + (-4 * -2x + x * -2x) + x2(-4 + x)) = 0
(12 + -3x + (8x + -2x2) + x2(-4 + x)) = 0
(12 + -3x + 8x + -2x2 + (-4 * x2 + x * x2)) = 0
(12 + -3x + 8x + -2x2 + (-4x2 + x3)) = 0

Combine like terms: -3x + 8x = 5x
(12 + 5x + -2x2 + -4x2 + x3) = 0

Combine like terms: -2x2 + -4x2 = -6x2
(12 + 5x + -6x2 + x3) = 0

Solving
12 + 5x + -6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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