(x-3)(x+11)=2x

Solution for (x-3)(x+11)=2x equation:

(x-3)(x+11)=2x

We move all terms to the left:

(x-3)(x+11)-(2x)=0

We add all the numbers together, and all the variables

-2x+(x-3)(x+11)=0

We multiply parentheses ..

(+x^2+11x-3x-33)-2x=0

We get rid of parentheses

x^2+11x-3x-2x-33=0

We add all the numbers together, and all the variables

x^2+6x-33=0

a = 1; b = 6; c = -33;
Δ = b2-4ac
Δ = 62-4·1·(-33)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{42}}{2*1}=\frac{-6-2\sqrt{42}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{42}}{2*1}=\frac{-6+2\sqrt{42}}{2}
$