(x-3)(x+13)=(x+3)(2x+6)

Solution for (x-3)(x+13)=(x+3)(2x+6) equation:

(x-3)(x+13)=(x+3)(2x+6)

We move all terms to the left:

(x-3)(x+13)-((x+3)(2x+6))=0

We multiply parentheses ..

(+x^2+13x-3x-39)-((x+3)(2x+6))=0


We calculate terms in parentheses: -((x+3)(2x+6)), so:

(x+3)(2x+6)

We multiply parentheses ..

(+2x^2+6x+6x+18)

We get rid of parentheses

2x^2+6x+6x+18

We add all the numbers together, and all the variables

2x^2+12x+18

Back to the equation:

-(2x^2+12x+18)


We get rid of parentheses

x^2-2x^2+13x-3x-12x-39-18=0

We add all the numbers together, and all the variables

-1x^2-2x-57=0

a = -1; b = -2; c = -57;
Δ = b2-4ac
Δ = -22-4·(-1)·(-57)
Δ = -224
Delta is less than zero, so there is no solution for the equation