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(x-3)(x+2)/3+1/2=3(1-2x)
We move all terms to the left:
(x-3)(x+2)/3+1/2-(3(1-2x))=0
We add all the numbers together, and all the variables
(x-3)(x+2)/3-(3(-2x+1))+1/2=0
We multiply parentheses ..
(+x^2+2x-3x-6)/3-(3(-2x+1))+1/2=0
We calculate fractions
There is no solution for this equation
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