(x-3)(x+2)=(x+1)(x-4)

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Solution for (x-3)(x+2)=(x+1)(x-4) equation: 



(x-3)(x+2)=(x+1)(x-4)

We move all terms to the left:

(x-3)(x+2)-((x+1)(x-4))=0

We multiply parentheses ..

(+x^2+2x-3x-6)-((x+1)(x-4))=0



We calculate terms in parentheses: -((x+1)(x-4)), so:

(x+1)(x-4)

We multiply parentheses ..

(+x^2-4x+x-4)

We get rid of parentheses

x^2-4x+x-4

We add all the numbers together, and all the variables

x^2-3x-4

Back to the equation:

-(x^2-3x-4)



We get rid of parentheses

x^2-x^2+2x-3x+3x-6+4=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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