(x-3)(x+3)(2x+1)=0

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Solution for (x-3)(x+3)(2x+1)=0 equation: 


Simplifying
(x + -3)(x + 3)(2x + 1) = 0

Reorder the terms:
(-3 + x)(x + 3)(2x + 1) = 0

Reorder the terms:
(-3 + x)(3 + x)(2x + 1) = 0

Reorder the terms:
(-3 + x)(3 + x)(1 + 2x) = 0

Multiply (-3 + x) * (3 + x)
(-3(3 + x) + x(3 + x))(1 + 2x) = 0
((3 * -3 + x * -3) + x(3 + x))(1 + 2x) = 0
((-9 + -3x) + x(3 + x))(1 + 2x) = 0
(-9 + -3x + (3 * x + x * x))(1 + 2x) = 0
(-9 + -3x + (3x + x2))(1 + 2x) = 0

Combine like terms: -3x + 3x = 0
(-9 + 0 + x2)(1 + 2x) = 0
(-9 + x2)(1 + 2x) = 0

Multiply (-9 + x2) * (1 + 2x)
(-9(1 + 2x) + x2(1 + 2x)) = 0
((1 * -9 + 2x * -9) + x2(1 + 2x)) = 0
((-9 + -18x) + x2(1 + 2x)) = 0
(-9 + -18x + (1 * x2 + 2x * x2)) = 0
(-9 + -18x + (1x2 + 2x3)) = 0
(-9 + -18x + 1x2 + 2x3) = 0

Solving
-9 + -18x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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