If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x-3)(x+4)=(x+2)-1
We move all terms to the left:
(x-3)(x+4)-((x+2)-1)=0
We multiply parentheses ..
(+x^2+4x-3x-12)-((x+2)-1)=0
We calculate terms in parentheses: -((x+2)-1), so:We get rid of parentheses
(x+2)-1
We get rid of parentheses
x+2-1
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
x^2+4x-3x-x-12-1=0
We add all the numbers together, and all the variables
x^2-13=0
a = 1; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·1·(-13)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{13}}{2*1}=\frac{0-2\sqrt{13}}{2} =-\frac{2\sqrt{13}}{2} =-\sqrt{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{13}}{2*1}=\frac{0+2\sqrt{13}}{2} =\frac{2\sqrt{13}}{2} =\sqrt{13} $
| 13x-6/9=14 | | -1/5b=1/15 | | 60/30=t | | x/1/4(5x+4)=1/3(2x-1) | | 28t-4.9t^2=0 | | 7(3-x)=-46.2 | | -1/8y=34 | | K^2-4k=30 | | 5n+6=18 | | 1/2f+6=5 | | 2/3x-17=21 | | 9x-14x=20 | | (2x)(x)(12)=2400 | | 8x/3-7=5 | | 4^x=3+18*4^(-x) | | 5^2+5x-30=0 | | 2a+3=47 | | x-8.86=7.71 | | 170(1/5)-450=y | | X^2+6x+9=78 | | X(2x-6)=154*2 | | y-7.7=15.1 | | 4x-8-4×=9 | | 282=238-w | | 4(3x-6)=3(5x-11) | | 4x-8-44×=9 | | 7(2x-6)=4(3x-8) | | 2y=y-4 | | 2(3+4x)=11(8x-14) | | 16y^2+8y-15=0 | | 10x=(6x+2) | | X=3;3x^2-21/3x |