(x-3)(x+4)=x(3)-7x-12

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Solution for (x-3)(x+4)=x(3)-7x-12 equation: 



(x-3)(x+4)=x(3)-7x-12

We move all terms to the left:

(x-3)(x+4)-(x(3)-7x-12)=0

We add all the numbers together, and all the variables

-(+x^3-7x-12)+(x-3)(x+4)=0

We get rid of parentheses

-x^3+7x+(x-3)(x+4)+12=0

We multiply parentheses ..

-x^3+(+x^2+4x-3x-12)+7x+12=0

We do not support expression: x^3

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