(x-3)(x+4)=x2

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Solution for (x-3)(x+4)=x2 equation:



(x-3)(x+4)=x2
We move all terms to the left:
(x-3)(x+4)-(x2)=0
We add all the numbers together, and all the variables
-1x^2+(x-3)(x+4)=0
We multiply parentheses ..
-1x^2+(+x^2+4x-3x-12)=0
We get rid of parentheses
-1x^2+x^2+4x-3x-12=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12

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