(x-3)(x+5)(x-9)(x+7)=378

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Solution for (x-3)(x+5)(x-9)(x+7)=378 equation: 



(x-3)(x+5)(x-9)(x+7)=378

We move all terms to the left:

(x-3)(x+5)(x-9)(x+7)-(378)=0

We multiply parentheses ..

(+x^2+5x-3x-15)(x-9)(x+7)-378=0

We multiply parentheses ..

(+x^2+5x-3x-15)(+x^2+7x-9x-63)-378=0

We move all terms containing x to the left, all other terms to the right

(+x^2+5x-3x-15)(+x^2+7x-9x-63)=378

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