(x-3)(x+6)=(x-4)(x-5)

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Solution for (x-3)(x+6)=(x-4)(x-5) equation: 



(x-3)(x+6)=(x-4)(x-5)

We move all terms to the left:

(x-3)(x+6)-((x-4)(x-5))=0

We multiply parentheses ..

(+x^2+6x-3x-18)-((x-4)(x-5))=0



We calculate terms in parentheses: -((x-4)(x-5)), so:

(x-4)(x-5)

We multiply parentheses ..

(+x^2-5x-4x+20)

We get rid of parentheses

x^2-5x-4x+20

We add all the numbers together, and all the variables

x^2-9x+20

Back to the equation:

-(x^2-9x+20)



We get rid of parentheses

x^2-x^2+6x-3x+9x-18-20=0

We add all the numbers together, and all the variables

12x-38=0

We move all terms containing x to the left, all other terms to the right

12x=38

x=38/12

x=3+1/6

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