(x-3)(x+7)=(x+3)(x-1)

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Solution for (x-3)(x+7)=(x+3)(x-1) equation: 



(x-3)(x+7)=(x+3)(x-1)

We move all terms to the left:

(x-3)(x+7)-((x+3)(x-1))=0

We multiply parentheses ..

(+x^2+7x-3x-21)-((x+3)(x-1))=0



We calculate terms in parentheses: -((x+3)(x-1)), so:

(x+3)(x-1)

We multiply parentheses ..

(+x^2-1x+3x-3)

We get rid of parentheses

x^2-1x+3x-3

We add all the numbers together, and all the variables

x^2+2x-3

Back to the equation:

-(x^2+2x-3)



We get rid of parentheses

x^2-x^2+7x-3x-2x-21+3=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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