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(x-3)(x+8)(x-5)=x
We move all terms to the left:
(x-3)(x+8)(x-5)-(x)=0
We add all the numbers together, and all the variables
-1x+(x-3)(x+8)(x-5)=0
We multiply parentheses ..
(+x^2+8x-3x-24)(x-5)-1x=0
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