(x-3)(x-1)=x(2+x)-40

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Solution for (x-3)(x-1)=x(2+x)-40 equation:



(x-3)(x-1)=x(2+x)-40
We move all terms to the left:
(x-3)(x-1)-(x(2+x)-40)=0
We add all the numbers together, and all the variables
(x-3)(x-1)-(x(x+2)-40)=0
We multiply parentheses ..
(+x^2-1x-3x+3)-(x(x+2)-40)=0
We calculate terms in parentheses: -(x(x+2)-40), so:
x(x+2)-40
We multiply parentheses
x^2+2x-40
Back to the equation:
-(x^2+2x-40)
We get rid of parentheses
x^2-x^2-1x-3x-2x+3+40=0
We add all the numbers together, and all the variables
-6x+43=0
We move all terms containing x to the left, all other terms to the right
-6x=-43
x=-43/-6
x=7+1/6

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