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(x-3)(x-2)=3.75
We move all terms to the left:
(x-3)(x-2)-(3.75)=0
We add all the numbers together, and all the variables
(x-3)(x-2)-3.75=0
We multiply parentheses ..
(+x^2-2x-3x+6)-3.75=0
We get rid of parentheses
x^2-2x-3x+6-3.75=0
We add all the numbers together, and all the variables
x^2-5x+2.25=0
a = 1; b = -5; c = +2.25;
Δ = b2-4ac
Δ = -52-4·1·2.25
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-4}{2*1}=\frac{1}{2} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+4}{2*1}=\frac{9}{2} =4+1/2 $
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