(x-3)(x-2)=6

Solution for (x-3)(x-2)=6 equation:

(x-3)(x-2)=6

We move all terms to the left:

(x-3)(x-2)-(6)=0

We multiply parentheses ..

(+x^2-2x-3x+6)-6=0

We get rid of parentheses

x^2-2x-3x+6-6=0

We add all the numbers together, and all the variables

x^2-5x=0

a = 1; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·1·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*1}=\frac{10}{2}
=5
$