(x-3)(x-3)+8=0

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Solution for (x-3)(x-3)+8=0 equation: 



(x-3)(x-3)+8=0

We multiply parentheses ..

(+x^2-3x-3x+9)+8=0

We get rid of parentheses

x^2-3x-3x+9+8=0

We add all the numbers together, and all the variables

x^2-6x+17=0

a = 1; b = -6; c = +17;
Δ = b2-4ac
Δ = -62-4·1·17
Δ = -32
Delta is less than zero, so there is no solution for the equation

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