(x-3)(x-4)=x*x+4

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Solution for (x-3)(x-4)=x*x+4 equation: 



(x-3)(x-4)=x*x+4

We move all terms to the left:

(x-3)(x-4)-(x*x+4)=0

We get rid of parentheses

(x-3)(x-4)-x*x-4=0

We multiply parentheses ..

(+x^2-4x-3x+12)-x*x-4=0

Wy multiply elements

(+x^2-4x-3x+12)-1x^2-4=0

We get rid of parentheses

x^2-1x^2-4x-3x+12-4=0

We add all the numbers together, and all the variables

-7x+8=0

We move all terms containing x to the left, all other terms to the right

-7x=-8

x=-8/-7

x=1+1/7

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