(x-3)(x-4)=x*x+4

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Solution for (x-3)(x-4)=x*x+4 equation:



(x-3)(x-4)=x*x+4
We move all terms to the left:
(x-3)(x-4)-(x*x+4)=0
We get rid of parentheses
(x-3)(x-4)-x*x-4=0
We multiply parentheses ..
(+x^2-4x-3x+12)-x*x-4=0
Wy multiply elements
(+x^2-4x-3x+12)-1x^2-4=0
We get rid of parentheses
x^2-1x^2-4x-3x+12-4=0
We add all the numbers together, and all the variables
-7x+8=0
We move all terms containing x to the left, all other terms to the right
-7x=-8
x=-8/-7
x=1+1/7

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