(x-3)(x-5)=(x+2)(x-3)+25

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Solution for (x-3)(x-5)=(x+2)(x-3)+25 equation: 



(x-3)(x-5)=(x+2)(x-3)+25

We move all terms to the left:

(x-3)(x-5)-((x+2)(x-3)+25)=0

We multiply parentheses ..

(+x^2-5x-3x+15)-((x+2)(x-3)+25)=0



We calculate terms in parentheses: -((x+2)(x-3)+25), so:

(x+2)(x-3)+25

We multiply parentheses ..

(+x^2-3x+2x-6)+25

We get rid of parentheses

x^2-3x+2x-6+25

We add all the numbers together, and all the variables

x^2-1x+19

Back to the equation:

-(x^2-1x+19)



We get rid of parentheses

x^2-x^2-5x-3x+1x+15-19=0

We add all the numbers together, and all the variables

-7x-4=0

We move all terms containing x to the left, all other terms to the right

-7x=4

x=4/-7

x=-4/7

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