(x-3)(x-5)=(x-2)(x-3)

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Solution for (x-3)(x-5)=(x-2)(x-3) equation: 



(x-3)(x-5)=(x-2)(x-3)

We move all terms to the left:

(x-3)(x-5)-((x-2)(x-3))=0

We multiply parentheses ..

(+x^2-5x-3x+15)-((x-2)(x-3))=0



We calculate terms in parentheses: -((x-2)(x-3)), so:

(x-2)(x-3)

We multiply parentheses ..

(+x^2-3x-2x+6)

We get rid of parentheses

x^2-3x-2x+6

We add all the numbers together, and all the variables

x^2-5x+6

Back to the equation:

-(x^2-5x+6)



We get rid of parentheses

x^2-x^2-5x-3x+5x+15-6=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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