(x-3)(y-4)=12

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Solution for (x-3)(y-4)=12 equation:


Simplifying
(x + -3)(y + -4) = 12

Reorder the terms:
(-3 + x)(y + -4) = 12

Reorder the terms:
(-3 + x)(-4 + y) = 12

Multiply (-3 + x) * (-4 + y)
(-3(-4 + y) + x(-4 + y)) = 12
((-4 * -3 + y * -3) + x(-4 + y)) = 12
((12 + -3y) + x(-4 + y)) = 12
(12 + -3y + (-4 * x + y * x)) = 12
(12 + -3y + (-4x + xy)) = 12

Reorder the terms:
(12 + -4x + xy + -3y) = 12
(12 + -4x + xy + -3y) = 12

Add '-12' to each side of the equation.
12 + -4x + xy + -12 + -3y = 12 + -12

Reorder the terms:
12 + -12 + -4x + xy + -3y = 12 + -12

Combine like terms: 12 + -12 = 0
0 + -4x + xy + -3y = 12 + -12
-4x + xy + -3y = 12 + -12

Combine like terms: 12 + -12 = 0
-4x + xy + -3y = 0

Solving
-4x + xy + -3y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3y' to each side of the equation.
-4x + xy + -3y + 3y = 0 + 3y

Combine like terms: -3y + 3y = 0
-4x + xy + 0 = 0 + 3y
-4x + xy = 0 + 3y
Remove the zero:
-4x + xy = 3y

Combine like terms: 3y + -3y = 0
-4x + xy + -3y = 0

The solution to this equation could not be determined.

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