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(x-3)(4-3x)=3x(2-x)+5
We move all terms to the left:
(x-3)(4-3x)-(3x(2-x)+5)=0
We add all the numbers together, and all the variables
(x-3)(-3x+4)-(3x(-1x+2)+5)=0
We multiply parentheses ..
(-3x^2+4x+9x-12)-(3x(-1x+2)+5)=0
We calculate terms in parentheses: -(3x(-1x+2)+5), so:We get rid of parentheses
3x(-1x+2)+5
We multiply parentheses
-3x^2+6x+5
Back to the equation:
-(-3x^2+6x+5)
-3x^2+3x^2+4x+9x-6x-12-5=0
We add all the numbers together, and all the variables
7x-17=0
We move all terms containing x to the left, all other terms to the right
7x=17
x=17/7
x=2+3/7
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