(x-3)+18=6(2x-3)

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Solution for (x-3)+18=6(2x-3) equation: 



(x-3)+18=6(2x-3)

We move all terms to the left:

(x-3)+18-(6(2x-3))=0

We get rid of parentheses

x-(6(2x-3))-3+18=0



We calculate terms in parentheses: -(6(2x-3)), so:

6(2x-3)

We multiply parentheses

12x-18

Back to the equation:

-(12x-18)



We add all the numbers together, and all the variables

x-(12x-18)+15=0

We get rid of parentheses

x-12x+18+15=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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