(x-3)+3x=(3x+44)-2

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Solution for (x-3)+3x=(3x+44)-2 equation: 



(x-3)+3x=(3x+44)-2

We move all terms to the left:

(x-3)+3x-((3x+44)-2)=0

We add all the numbers together, and all the variables

3x+(x-3)-((3x+44)-2)=0

We get rid of parentheses

3x+x-((3x+44)-2)-3=0



We calculate terms in parentheses: -((3x+44)-2), so:

(3x+44)-2

We get rid of parentheses

3x+44-2

We add all the numbers together, and all the variables

3x+42

Back to the equation:

-(3x+42)



We add all the numbers together, and all the variables

4x-(3x+42)-3=0

We get rid of parentheses

4x-3x-42-3=0

We add all the numbers together, and all the variables

x-45=0

We move all terms containing x to the left, all other terms to the right

x=45

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