(x-3)+8x=5(2x+1)

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Solution for (x-3)+8x=5(2x+1) equation: 



(x-3)+8x=5(2x+1)

We move all terms to the left:

(x-3)+8x-(5(2x+1))=0

We add all the numbers together, and all the variables

8x+(x-3)-(5(2x+1))=0

We get rid of parentheses

8x+x-(5(2x+1))-3=0



We calculate terms in parentheses: -(5(2x+1)), so:

5(2x+1)

We multiply parentheses

10x+5

Back to the equation:

-(10x+5)



We add all the numbers together, and all the variables

9x-(10x+5)-3=0

We get rid of parentheses

9x-10x-5-3=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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