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(x-3)+x+(3x-1)+(x-5)=87
We move all terms to the left:
(x-3)+x+(3x-1)+(x-5)-(87)=0
We add all the numbers together, and all the variables
x+(x-3)+(3x-1)+(x-5)-87=0
We get rid of parentheses
x+x+3x+x-3-1-5-87=0
We add all the numbers together, and all the variables
6x-96=0
We move all terms containing x to the left, all other terms to the right
6x=96
x=96/6
x=16
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