(x-3)-(x+2)+2(x-1)-5=0

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Solution for (x-3)-(x+2)+2(x-1)-5=0 equation:


Simplifying
(x + -3) + -1(x + 2) + 2(x + -1) + -5 = 0

Reorder the terms:
(-3 + x) + -1(x + 2) + 2(x + -1) + -5 = 0

Remove parenthesis around (-3 + x)
-3 + x + -1(x + 2) + 2(x + -1) + -5 = 0

Reorder the terms:
-3 + x + -1(2 + x) + 2(x + -1) + -5 = 0
-3 + x + (2 * -1 + x * -1) + 2(x + -1) + -5 = 0
-3 + x + (-2 + -1x) + 2(x + -1) + -5 = 0

Reorder the terms:
-3 + x + -2 + -1x + 2(-1 + x) + -5 = 0
-3 + x + -2 + -1x + (-1 * 2 + x * 2) + -5 = 0
-3 + x + -2 + -1x + (-2 + 2x) + -5 = 0

Reorder the terms:
-3 + -2 + -2 + -5 + x + -1x + 2x = 0

Combine like terms: -3 + -2 = -5
-5 + -2 + -5 + x + -1x + 2x = 0

Combine like terms: -5 + -2 = -7
-7 + -5 + x + -1x + 2x = 0

Combine like terms: -7 + -5 = -12
-12 + x + -1x + 2x = 0

Combine like terms: x + -1x = 0
-12 + 0 + 2x = 0
-12 + 2x = 0

Solving
-12 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 2x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2x = 0 + 12
2x = 0 + 12

Combine like terms: 0 + 12 = 12
2x = 12

Divide each side by '2'.
x = 6

Simplifying
x = 6

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