(x-3)-5(x+2)=7(3x-1)+29

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Solution for (x-3)-5(x+2)=7(3x-1)+29 equation: 



(x-3)-5(x+2)=7(3x-1)+29

We move all terms to the left:

(x-3)-5(x+2)-(7(3x-1)+29)=0

We multiply parentheses

(x-3)-5x-(7(3x-1)+29)-10=0

We get rid of parentheses

x-5x-(7(3x-1)+29)-3-10=0



We calculate terms in parentheses: -(7(3x-1)+29), so:

7(3x-1)+29

We multiply parentheses

21x-7+29

We add all the numbers together, and all the variables

21x+22

Back to the equation:

-(21x+22)



We add all the numbers together, and all the variables

-4x-(21x+22)-13=0

We get rid of parentheses

-4x-21x-22-13=0

We add all the numbers together, and all the variables

-25x-35=0

We move all terms containing x to the left, all other terms to the right

-25x=35

x=35/-25

x=-1+2/5

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