(x-3)/(3x)+1=(x+2)/(x)

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Solution for (x-3)/(3x)+1=(x+2)/(x) equation: 



(x-3)/(3x)+1=(x+2)/(x)

We move all terms to the left:

(x-3)/(3x)+1-((x+2)/(x))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(x-3)*x)/3x^2+(-((x+2)*3x)/3x^2+1=0

We calculate fractions


((x-3)*x)*3x^2)/(3x^2+(*3x^2)+(-((x+2)*3x)*3x^2)/(3x^2+(*3x^2)+1=0

We get rid of parentheses

((x-3)*x)*3x^2)/(3x^2+*3x^2+(-((x+2)*3x)*3x^2)/(3x^2+(*3x^2)+1=0

We calculate fractions


*3x^2+(((x-3)*x)*3x^2)*(3x^2+*3x^2+1)/((3x^2*(3x^2+(*3x^2)+1)+((-((x+2)*3x)*3x^2)*3x^2/((3x^2*(3x^2+(*3x^2)+1)=0



We calculate terms in parentheses: +(((x-3)*x)*3x^2)*(3x^2+*3x^2+1)/((3x^2*(3x^2+(*3x^2)+1)+((-((x+2)*3x)*3x^2)*3x^2/((3x^2*(3x^2+(*3x^2)+1), so:

((x-3)*x)*3x^2)*(3x^2+*3x^2+1)/((3x^2*(3x^2+(*3x^2)+1)+((-((x+2)*3x)*3x^2)*3x^2/((3x^2*(3x^2+(*3x^2)+1

We can not solve this equation

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