(x-3)/(3x+1)=2

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Solution for (x-3)/(3x+1)=2 equation: 



(x-3)/(3x+1)=2

We move all terms to the left:

(x-3)/(3x+1)-(2)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R



We multiply all the terms by the denominator


(x-3)-2*(3x+1)=0

We multiply parentheses

(x-3)-6x-2=0

We get rid of parentheses

x-6x-3-2=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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