(x-3)/(x+5)=x/(x+2)

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Solution for (x-3)/(x+5)=x/(x+2) equation: 



(x-3)/(x+5)=x/(x+2)

We move all terms to the left:

(x-3)/(x+5)-(x/(x+2))=0



Domain of the equation: (x+5)!=0

We move all terms containing x to the left, all other terms to the right

x!=-5

x∈R





Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


((x-3)*(x+2)))/((x+5)*(x+2)))+(-(x*(x+5))/((x+5)*(x+2)))=0



We calculate terms in parentheses: +((x-3)*(x+2)))/((x+5)*(x+2)))+(-(x*(x+5))/((x+5)*(x+2))), so:

(x-3)*(x+2)))/((x+5)*(x+2)))+(-(x*(x+5))/((x+5)*(x+2))

We add all the numbers together, and all the variables

(x-3)*(x+2)))/((x+5)*(x+2)))+(-(x*(x+5))/((x+5)*(x

We multiply all the terms by the denominator


(x-3)*(x+2)))+5*x*((x+2))+(-(x*x*((x+5))+5*x*((x

Wy multiply elements

5x^2*(+(x-3)*(x+2)))+5*x*((x+2))+(-(x*x*((x+5))



We calculate terms in parentheses: -(x*x*((x+5)), so:

x*x*((x+5)

Wy multiply elements

x^3*(

We do not support expression: x^3

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