(x-3)/2+(2x+6)/7=(11x-9)/14

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Solution for (x-3)/2+(2x+6)/7=(11x-9)/14 equation:


(x-3)/2+(2x+6)/7=(11x-9)/14

We simplify the equation to the form, which is simple to understand
(x-3)/2+(2x+6)/7=(11x-9)/14

Reorder the terms in parentheses
( + 0.5x-1.5)+(2x+6)/7=(11x-9)/14

Remove unnecessary parentheses
+ 0.5x-1.5+(2x+6)/7=(11x-9)/14

Reorder the terms in parentheses
+ 0.5x-1.5+( + 0.285714285714x + 0.857142857143)=(11x-9)/14

Remove unnecessary parentheses
+ 0.5x-1.5 + 0.285714285714x + 0.857142857143=+(+11x-9+)+/14

Reorder the terms in parentheses
+ 0.5x-1.5 + 0.285714285714x + 0.857142857143=( + 0.785714285714x-0.642857142857)

Remove unnecessary parentheses
+ 0.5x-1.5 + 0.285714285714x + 0.857142857143=0.785714285714x-0.642857142857

We move all terms containing x to the left and all other terms to the right.
+ 0.5x + 0.285714285714x-0.785714285714x=-0.642857142857+1.5-0.857142857143

We simplify left and right side of the equation.
+2.85660384236E-13x=0

We divide both sides of the equation by 2.85660384236E-13 to get x.
x=0

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