(x-3)/2+(3/2)=-x/5

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Solution for (x-3)/2+(3/2)=-x/5 equation: 


x in (-oo:+oo)

(x-3)/2+3/2 = -x/5 // + -x/5

(x-3)/2-(-x/5)+3/2 = 0

(x-3)/2+(1/5)*x+3/2 = 0

(x-3)/2+x/5+3/2 = 0

(5*(x-3))/(2*5)+(2*x)/(2*5)+(3*5)/(2*5) = 0

5*(x-3)+2*x+3*5 = 0

7*x-15+15 = 0

7*x = 0

(7*x)/(2*5) = 0

(7*x)/(2*5) = 0 // * 2*5

7*x = 0

7*x = 0 // : 7

x = 0

x = 0

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