(x-3)/2=(2x+4)/5

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Solution for (x-3)/2=(2x+4)/5 equation: 



(x-3)/2=(2x+4)/5

We move all terms to the left:

(x-3)/2-((2x+4)/5)=0

We calculate fractions


x/()+(-((2x+4)*2)/()=0



We calculate terms in parentheses: +(-((2x+4)*2)/(), so:

-((2x+4)*2)/(

We multiply all the terms by the denominator


-((2x+4)*2)



We calculate terms in parentheses: -((2x+4)*2), so:

(2x+4)*2

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

-4x-8

Back to the equation:

+(-4x-8)



We get rid of parentheses

x/()-4x-8=0

We multiply all the terms by the denominator


x-4x*()-8*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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