(x-3)/2=(5x+1)/6

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Solution for (x-3)/2=(5x+1)/6 equation: 



(x-3)/2=(5x+1)/6

We move all terms to the left:

(x-3)/2-((5x+1)/6)=0

We calculate fractions


x/()+(-((5x+1)*2)/()=0



We calculate terms in parentheses: +(-((5x+1)*2)/(), so:

-((5x+1)*2)/(

We multiply all the terms by the denominator


-((5x+1)*2)



We calculate terms in parentheses: -((5x+1)*2), so:

(5x+1)*2

We multiply parentheses

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

-10x-2

Back to the equation:

+(-10x-2)



We get rid of parentheses

x/()-10x-2=0

We multiply all the terms by the denominator


x-10x*()-2*()=0

We add all the numbers together, and all the variables

x-10x*()=0

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