(x-3)/3-(x+4)/12=(4x-3)/12

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Solution for (x-3)/3-(x+4)/12=(4x-3)/12 equation: 



(x-3)/3-(x+4)/12=(4x-3)/12

We move all terms to the left:

(x-3)/3-(x+4)/12-((4x-3)/12)=0

We calculate fractions


x/()+(-3x-12)/()+(-((4x-3)*3)/()=0



We calculate terms in parentheses: +(-((4x-3)*3)/(), so:

-((4x-3)*3)/(

We multiply all the terms by the denominator


-((4x-3)*3)



We calculate terms in parentheses: -((4x-3)*3), so:

(4x-3)*3

We multiply parentheses

12x-9

Back to the equation:

-(12x-9)



We get rid of parentheses

-12x+9

Back to the equation:

+(-12x+9)



We get rid of parentheses

x/()+(-3x-12)/()-12x+9=0

We multiply all the terms by the denominator


x+(-3x-12)-12x*()+9*()=0

We add all the numbers together, and all the variables

x+(-3x-12)-12x*()=0

We get rid of parentheses

x-3x-12x*()-12=0

We add all the numbers together, and all the variables

-2x-12x*()-12=0

We move all terms containing x to the left, all other terms to the right

-2x-12x*()=12

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