(x-3)/3=(x+4)/7

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Solution for (x-3)/3=(x+4)/7 equation: 



(x-3)/3=(x+4)/7

We move all terms to the left:

(x-3)/3-((x+4)/7)=0

We calculate fractions


x/()+(-((x+4)*3)/()=0



We calculate terms in parentheses: +(-((x+4)*3)/(), so:

-((x+4)*3)/(

We multiply all the terms by the denominator


-((x+4)*3)



We calculate terms in parentheses: -((x+4)*3), so:

(x+4)*3

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-3x-12

Back to the equation:

+(-3x-12)



We get rid of parentheses

x/()-3x-12=0

We multiply all the terms by the denominator


x-3x*()-12*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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