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(x-3)/3=(x+4)/7
We move all terms to the left:
(x-3)/3-((x+4)/7)=0
We calculate fractions
x/()+(-((x+4)*3)/()=0
We calculate terms in parentheses: +(-((x+4)*3)/(), so:We get rid of parentheses
-((x+4)*3)/(
We multiply all the terms by the denominator
-((x+4)*3)
We calculate terms in parentheses: -((x+4)*3), so:We get rid of parentheses
(x+4)*3
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
-3x-12
Back to the equation:
+(-3x-12)
x/()-3x-12=0
We multiply all the terms by the denominator
x-3x*()-12*()=0
We add all the numbers together, and all the variables
x-3x*()=0
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