(x-3)/5-1=(x-5)/5

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Solution for (x-3)/5-1=(x-5)/5 equation: 


x in (-oo:+oo)

(x-3)/5-1 = (x-5)/5 // - (x-5)/5

(x-3)/5-((x-5)/5)-1 = 0

(x-3)/5+(-1*(x-5))/5-1 = 0

(x-3)/5+(-1*(x-5))/5+(-1*5)/5 = 0

x-1*(x-5)-1*5-3 = 0

2-5 = 0

-3 = 0

-3/5 = 0

-3/5 = 0 // * 5

-3 = 0

-3 = 0

x belongs to the empty set

x belongs to the empty set

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