(x-3)/7=(x+5)/6

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Solution for (x-3)/7=(x+5)/6 equation: 



(x-3)/7=(x+5)/6

We move all terms to the left:

(x-3)/7-((x+5)/6)=0

We calculate fractions


x/()+(-((x+5)*7)/()=0



We calculate terms in parentheses: +(-((x+5)*7)/(), so:

-((x+5)*7)/(

We multiply all the terms by the denominator


-((x+5)*7)



We calculate terms in parentheses: -((x+5)*7), so:

(x+5)*7

We multiply parentheses

7x+35

Back to the equation:

-(7x+35)



We get rid of parentheses

-7x-35

Back to the equation:

+(-7x-35)



We get rid of parentheses

x/()-7x-35=0

We multiply all the terms by the denominator


x-7x*()-35*()=0

We add all the numbers together, and all the variables

x-7x*()=0

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